Unhandled exception java text parseexception

java.text.ParseException

I keep getting an error on line 60. It says, «unreported exception java.text.ParseException; must be caught or declared to be thrown» I’ve looked it up and everything i’m reading says I have an error in my date formats, but I can’t figure out what it would be, as they all seem to be formatted the same way.

Create a Map and add ten entries that represent (last name, birth date) pairs.
Remove from the map all people born in the summer.
Hint: At CodeGym, summer lasts from June 1 to August 31.

The createMap() method must create and return a HashMap that has (String, Date) elements and contains 10 entries.

package com.codegym.task.task08.task0816; import java.text.DateFormat; import java.text.ParseException; import java.text.SimpleDateFormat; import java.util.*; import java.util.Calendar; import java.util.Map; import java.util.Locale; import java.util.Iterator; import java.util.Date; import java.util.HashMap; /* Kind Emma and the summer holidays */ public class Solution < public static HashMapcreateMap() throws ParseException < DateFormat dateFormat = new SimpleDateFormat("MMMMM d yyyy", Locale.ENGLISH); HashMapmap = new HashMap<>(); map.put(«Stallone», dateFormat.parse(«JUNE 1 1980»)); map.put(«Pace», dateFormat.parse(«JANUARY 9 2018»)); map.put(«Jones», dateFormat.parse(«SEPTEMBER 1 1999»)); map.put(«Bloomquist», dateFormat.parse(«MARCH 5 1991»)); map.put(«Legg», dateFormat.parse(«NOVEMBER 8 1989»)); map.put(«Nash», dateFormat.parse(«JUNE 7 1995»)); map.put(«Paterson», dateFormat.parse(«APRIL 4 1980»)); map.put(«Gold», dateFormat.parse(«JULY 3 1971»)); map.put(«Redd»,dateFormat.parse(«AUGUST 2 1990»)); map.put(«Blue», dateFormat.parse(«DECEMBER 5 1999»)); return map; > public static void removeAllSummerPeople(HashMap map) < Calendar cal = Calendar.getInstance(); Iterator> itr = map.entrySet().iterator(); while (itr.hasNext()) < Map.Entryentry = itr.next(); cal.setTime(entry.getValue()); if (cal.get(Calendar.MONTH)== 5 || cal.get(Calendar.MONTH)== 6 || cal.get(Calendar.MONTH)== 7) < itr.remove(); >> > public static void main(String[] args) < HashMapnameMap = new HashMap<>(); nameMap = createMap(); // unhandled exception here removeAllSummerPeople(nameMap); > >

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[Solved] Date Format Error: java.text.parseexception: unparseable date

Why you are getting java.text.parseexception unparseable date?

You may have come across “java.text.parseexception: unparseable date” error message, when you try to parse the date string into another desired format. Don’t worry it’s a very common error message that users generally faced while parsing a date in java using SimpleDateFormat class.

There are mainly three reasons for this error message either your date format is wrong or you are using the wrong localization or the time zone is not correct. In this article, we are going to see all these three aspects of date parsing which may result in the “java.text.parseexception: unparseable error” message.

What is mean by java.text.parseexception unparseable date?

Let’s first try to understand the error message thoroughly. If you read the error message carefully it’s saying that SimpleDateFormat class is not able to parse the input date string in the desired format.

java.text.parseexception is a runtime exception that occurs when there is a mismatch in the Input Date String value and the Format specified for parsing.

Three Important elements you must consider while parsing a date

Before going further let’s first understand the following three important elements of parsing a date into the required format.

Date Format is very important while parsing the date string into another format. All elements of the date format are case-sensitive. A slight change in the format may result in errors or unexpected results. Refer following table to understand characters used to represent different elements of the date.

Use the following syntax to specify the date format.

SimpleDateFormat dateFormat = new SimpleDateFormat("your-date-format");

SimpleDateFormat dateFormat = new SimpleDateFormat("dd-MM-YYYY HH:mm:ss");

Localization is very important when using SimpleDateFormat class to parse the date format. If you don’t specify the locale then the constructor of the SimpleDateFormat class uses the default systems locale.

If your input date string is in English locale and if you tried to parse it without specifying localization on the system which is Non-English then it will result in the java.text.parseexception unparseable date error.

You can specify locale explicitly while defining the date format as shown below.

SimpleDateFormat dateFormat = new SimpleDateFormat("your-date-format", Locale.English)

The correct time zone is also very critical while formatting a date in the desired format. The constructor of SimpleDateFormat class implicitly uses JVM default current time zone. JVM’s default current time zone can change based on the location of the user. If a thread of any other application changes the default time zone of JVM then it will result in an unexpected error or wrong output. So it’s advisable to specify Time Zone explicitly while formatting the date.

You can specify the required timezone while formatting a date as shown below.

 dateFormat.setTimeZone(TimeZone.getTimeZone("UTC"));

Now we will see three different examples where you may get java.text.ParseException: Unparseable date error message.

Example 1: Invalid Input String Format

package com.technolads; import java.text.ParseException; import java.text.SimpleDateFormat; import java.util.Date; import java.util.Locale; public class ChangeDateFormat < public static void main(String[] args) < try < // Input Date String String inputDateString = "Feb 25 02:10:36 2021"; // Input Date String Format SimpleDateFormat inputDateFormat = new SimpleDateFormat("MM dd HH:mm:ss yyyy", Locale.ENGLISH); Date inputDate = inputDateFormat.parse(inputDateString); //Required output date string Format SimpleDateFormat outputDateFormat = new SimpleDateFormat("dd MMMMMM yyyy HH:mm:ss", Locale.ENGLISH); String outputDateString = outputDateFormat.format(inputDate); System.out.println("inputDateString: "+inputDateString); System.out.println("outputDateString: " +outputDateString); >catch (ParseException e) < // TODO Auto-generated catch block e.printStackTrace(); >> >

java.text.ParseException: Unparseable date: "Feb 25 02:10:36 2021" at java.base/java.text.DateFormat.parse(DateFormat.java:399) at com.technolads.ChangeDateFormat.main(ChangeDateFormat.java:20)

As you see in the above example, the Month of the Input date string is 3 characters (Feb) but in the input date format, a month is specified by 2 characters only (MM). That’s why we got an error message. If you use three characters (MMM) in the input date format then the code will execute without any error message.

Modify code an the line number 18 as shown below:

SimpleDateFormat inputDateFormat = new SimpleDateFormat("MMM dd HH:mm:ss yyyy", Locale.ENGLISH);

Example 2: Invalid Locale

package com.technolads; import java.text.ParseException; import java.text.SimpleDateFormat; import java.util.Date; import java.util.Locale; public class ChangeDateFormat < public static void main(String[] args) < try < // Input Date String String inputDateString = "Aug 25 02:10:36 2021"; // Input Date String Format SimpleDateFormat inputDateFormat = new SimpleDateFormat("MMM dd HH:mm:ss yyyy", Locale.ITALY); //Wrong Localization Date inputDate = inputDateFormat.parse(inputDateString); //Required output date string Format SimpleDateFormat outputDateFormat = new SimpleDateFormat("dd MMMMMM yyyy HH:mm:ss", Locale.ENGLISH); String outputDateString = outputDateFormat.format(inputDate); System.out.println("inputDateString: "+inputDateString); System.out.println("outputDateString: " +outputDateString); >catch (ParseException e) < // TODO Auto-generated catch block e.printStackTrace(); >> >

java.text.ParseException: Unparseable date: "Aug 25 02:10:36 2021" at java.base/java.text.DateFormat.parse(DateFormat.java:399) at com.technolads.ChangeDateFormat.main(ChangeDateFormat.java:20)

As you see in the above example at line number 18 instead of ENGLISH, ITALY localization is used which caused the error message. In Italian Aug is written as Agosto. If your input contains Italian characters like Agosto then only use ITALY as a locale. Here Aug is an English word hence you must use ENGLISH as a locale.

Modify code an the line number 18 as shown below:

SimpleDateFormat inputDateFormat = new SimpleDateFormat("MMM dd HH:mm:ss yyyy", Locale.ENGLISH);

Example 3: Invalid Time Zone

package com.technolads; import java.text.ParseException; import java.text.SimpleDateFormat; import java.util.Date; import java.util.Locale; import java.util.TimeZone; public class ChangeDateFormat < public static void main(String[] args) < try < // Input Date String String inputDateString = "2021-08-25T09:18:25.758Z"; // Input Date String Format SimpleDateFormat inputDateFormat = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSSZ"); Date inputDate = inputDateFormat.parse(inputDateString); //Required output date string Format SimpleDateFormat outputDateFormat = new SimpleDateFormat("dd MMMMMM yyyy HH:mm:ss", Locale.ENGLISH); String outputDateString = outputDateFormat.format(inputDate); System.out.println("inputDateString: "+inputDateString); System.out.println("outputDateString: " +outputDateString); >catch (ParseException e) < // TODO Auto-generated catch block e.printStackTrace(); >> >

java.text.ParseException: Unparseable date: "2021-08-25T09:18:25.758Z" at java.base/java.text.DateFormat.parse(DateFormat.java:399) at com.technolads.ChangeDateFormat.main(ChangeDateFormat.java:22)

Add trailing Z represented as Time zone in the single quotes (‘Z’)

Modify line number 17 to as shown below:

SimpleDateFormat inputDateFormat = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSS'Z'");

Note: It may change the time based on the current time zone. To avoid this set required time zone, as explained above in the Time Zone section.

Conclusion:

We hope that the above methods helped you resolve the “java.text.parseexception: unparseable date” error message. If you are still facing the issue then please do mention it in the comment section or you can reach out to us using Contact Form.

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java.text.ParseException – How to Solve ParseException

In this example we are going to talk about java.text.ParseException . This is a checked exception an it can occur when you fail to parse a String that is ought to have a special format. One very significant example on that is when you are trying to parse a String to a Date Object. As you might know, that string should have a specified format. If the given string doesn’t meet that format a java.text.ParseException will be thrown.

Ok let’s see that in a code sample:

1. An example of java.text.ParseException

Here is a simple client that sets a specified date format and then tries to parse a String to a Date object:

package com.javacodegeeks.core.ParseException; import java.text.DateFormat; import java.text.ParseException; import java.text.SimpleDateFormat; import java.util.Date; public class ParseExceptionExample < public static void main(String[] args) < String dateStr = "2011-11-19"; DateFormat dateFormat = new SimpleDateFormat("yyyy-MM-dd"); Date date; try < date = dateFormat.parse(dateStr); System.out.println(date); >catch (ParseException e) < e.printStackTrace(); >> >

The output of this :

Sat Nov 19 00:00:00 EET 2011

String dateStr = "2011 11 19";

Try to run the program again, and you will get this error:

java.text.ParseException: Unparseable date: "2011 11 19" at java.text.DateFormat.parse(DateFormat.java:357) at com.javacodegeeks.core.ParseException.ParseExceptionExample.main(ParseExceptionExample.java:17)

2. How to solve java.text.ParseException

Well, there isn’t much you can do. There is no mystery surrounding this exception :). Obviously, there is something wrong either with the String you are providing to the parse() method, or with the Format you are providing. You should check again carefully both of these aspects, and of course develop a range of tests that confirm the correctness of your Format .

Download Source Code

This was an example on java.text.ParseException . You can download the source code of this example here : ParseExceptionExample.zip

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Проблемы с исключением «java.text.ParseException»

При компиляции выдаёт следующую ошибку: Исключение «java.text.ParseException» должно быть перехвачено в блоке try\catch или объявлено в сигнатуре метода. Хотя вроде в сигнатуре метода исключение объявлено, не могу понять в чём проблема. Заранее спасибо.

Создать словарь ( Map ) и занести в него десять записей по принципу: «фамилия» — «дата рождения».
Удалить из словаря всех людей, родившихся летом.

Метод createMap() должен создавать и возвращать словарь HashMap с типом элементов String, Date состоящий из 10 записей.

package com.javarush.task.task08.task0816; import java.text.DateFormat; import java.text.ParseException; import java.text.SimpleDateFormat; import java.util.*; /* Добрая Зинаида и летние каникулы */ public class Solution < public static HashMapcreateMap() throws ParseException < DateFormat df = new SimpleDateFormat("MMMMM d yyyy", Locale.ENGLISH); HashMapmap = new HashMap(); map.put(«Stallone», df.parse(«JUNE 1 1980»)); //напишите тут ваш код map.put(«А», df.parse(«JUNE 1 1980»)); map.put(«В», df.parse(«SEPTEMBER 5 1980»)); map.put(«Ы», df.parse(«JULY 1 1980»)); map.put(«Ф», df.parse(«AUGUST 1 1980»)); map.put(«П», df.parse(«JANUARY 5 1980»)); map.put(«Л», df.parse(«FEBRUARY 1 1980»)); map.put(«д», df.parse(«JULY 1 1980»)); map.put(«к», df.parse(«OCTOBER 7 1980»)); map.put(«е», df.parse(«JUNE 1 1980»)); return map; > public static void removeAllSummerPeople(HashMap map) < for(Map.Entrycouple : map.entrySet()) < if(5 < couple.getValue().getMonth() && couple.getValue().getMonth() < 9) map.remove(couple.getKey()); >> public static void main(String[] args) < removeAllSummerPeople(createMap()); >>

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Проблемы с исключением «java.text.ParseException»

При компиляции выдаёт следующую ошибку: Исключение «java.text.ParseException» должно быть перехвачено в блоке try\catch или объявлено в сигнатуре метода. Хотя вроде в сигнатуре метода исключение объявлено, не могу понять в чём проблема. Заранее спасибо.

Создать словарь ( Map ) и занести в него десять записей по принципу: «фамилия» — «дата рождения».
Удалить из словаря всех людей, родившихся летом.

Метод createMap() должен создавать и возвращать словарь HashMap с типом элементов String, Date состоящий из 10 записей.

package com.javarush.task.task08.task0816; import java.text.DateFormat; import java.text.ParseException; import java.text.SimpleDateFormat; import java.util.*; /* Добрая Зинаида и летние каникулы */ public class Solution < public static HashMapcreateMap() throws ParseException < DateFormat df = new SimpleDateFormat("MMMMM d yyyy", Locale.ENGLISH); HashMapmap = new HashMap(); map.put(«Stallone», df.parse(«JUNE 1 1980»)); //напишите тут ваш код map.put(«А», df.parse(«JUNE 1 1980»)); map.put(«В», df.parse(«SEPTEMBER 5 1980»)); map.put(«Ы», df.parse(«JULY 1 1980»)); map.put(«Ф», df.parse(«AUGUST 1 1980»)); map.put(«П», df.parse(«JANUARY 5 1980»)); map.put(«Л», df.parse(«FEBRUARY 1 1980»)); map.put(«д», df.parse(«JULY 1 1980»)); map.put(«к», df.parse(«OCTOBER 7 1980»)); map.put(«е», df.parse(«JUNE 1 1980»)); return map; > public static void removeAllSummerPeople(HashMap map) < for(Map.Entrycouple : map.entrySet()) < if(5 < couple.getValue().getMonth() && couple.getValue().getMonth() < 9) map.remove(couple.getKey()); >> public static void main(String[] args) < removeAllSummerPeople(createMap()); >>

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