Set parameter value java

Set value for a class’ parameter in Java

Mean if set some other object to reference passed inside method, the object from calling method as well its reference will remain unaffected. Java creates a copy of references and pass it to method, but they still point to same memory reference.

Set value for a class’ parameter in Java

I have a java class which has a List as following:

public class TestEntity < private String name; private ListdataEntries; > class DataEntry

How could i add a DataEntry’s instance into a TestEntity’s instance?

First you need to ensure that your list is actually not null, like:

private final List entries = new ArrayList<>(); 

and then you can do something like

DataEntry entry = new DataEntry(); entry.para1 = . entries.add(entry); 

Of course, the more realistic thing would be to add a custom constructor to the DataEntry class, so that you can pass the required arguments via the constructor.

void addEntry(DataEntry entry) < entries.add(entry); 

Pretty simple if you just instantiate it.

dataEntries.add(new DataEntry()); 

There are two possiblities:

First: You add a constructor to add an entry:

public class TestEntity < private String name; private ListdataEntries; public TestEntity (String name,DataEntry entry)< this.name = Name; this.dataEntry = new ArrayList<>(); this.dataEntry.add(entry) > > 

Second: You add an addDataEntry function:

public class TestEntity < private String name; private ListdataEntries; public void addDataEntry(DataEntry entry)< if (this.dataEntry == null)< this.dataEntry = new ArrayList<>(); > this.dataEntry.add(entry) > > 

Simple parameter-value pairs in Java?, An object that maps keys to values. A map cannot contain duplicate keys; each key can map to at most one value. Try HashMap. Map

Passing Arguments by Value in Java

Adding Parameters to a Method & Returning Values

Get more lessons like this at http://www.MathTutorDVD.com Learn how to program in java with Duration: 24:21

Exercise 02x - Passing Parameters to a Method & Returning Values

Get more lessons like this at http://www.MathTutorDVD.comLearn how to program in java with
Duration: 7:04

Java is Strictly Pass by Value!

Consider the following Java program that passes a primitive type to function.

Java

We pass an int to the function “change()” and as a result the change in the value of that integer is not reflected in the main method. Like C/C++, Java creates a copy of the variable being passed in the method and then do the manipulations. Hence the change is not reflected in the main method.

How about objects or references?

In Java, all primitives like int, char, etc are similar to C/C++, but all non-primitives (or objects of any class) are always references. So it gets tricky when we pass object references to methods. Java creates a copy of references and pass it to method, but they still point to same memory reference. Mean if set some other object to reference passed inside method, the object from calling method as well its reference will remain unaffected. The changes are not reflected back if we change the object itself to refer some other location or object If we assign reference to some other location, then changes are not reflected back in main().

Источник

Passing Information to a Method or a Constructor

The declaration for a method or a constructor declares the number and the type of the arguments for that method or constructor. For example, the following is a method that computes the monthly payments for a home loan, based on the amount of the loan, the interest rate, the length of the loan (the number of periods), and the future value of the loan:

public double computePayment( double loanAmt, double rate, double futureValue, int numPeriods) < double interest = rate / 100.0; double partial1 = Math.pow((1 + interest), - numPeriods); double denominator = (1 - partial1) / interest; double answer = (-loanAmt / denominator) - ((futureValue * partial1) / denominator); return answer; >

This method has four parameters: the loan amount, the interest rate, the future value and the number of periods. The first three are double-precision floating point numbers, and the fourth is an integer. The parameters are used in the method body and at runtime will take on the values of the arguments that are passed in.

Note: Parameters refers to the list of variables in a method declaration. Arguments are the actual values that are passed in when the method is invoked. When you invoke a method, the arguments used must match the declaration's parameters in type and order.

Parameter Types

You can use any data type for a parameter of a method or a constructor. This includes primitive data types, such as doubles, floats, and integers, as you saw in the computePayment method, and reference data types, such as objects and arrays.

Here's an example of a method that accepts an array as an argument. In this example, the method creates a new Polygon object and initializes it from an array of Point objects (assume that Point is a class that represents an x, y coordinate):

public Polygon polygonFrom(Point[] corners) < // method body goes here >

Note: If you want to pass a method into a method, then use a lambda expression or a method reference.

Arbitrary Number of Arguments

You can use a construct called varargs to pass an arbitrary number of values to a method. You use varargs when you don't know how many of a particular type of argument will be passed to the method. It's a shortcut to creating an array manually (the previous method could have used varargs rather than an array).

To use varargs, you follow the type of the last parameter by an ellipsis (three dots, . ), then a space, and the parameter name. The method can then be called with any number of that parameter, including none.

public Polygon polygonFrom(Point. corners) < int numberOfSides = corners.length; double squareOfSide1, lengthOfSide1; squareOfSide1 = (corners[1].x - corners[0].x) * (corners[1].x - corners[0].x) + (corners[1].y - corners[0].y) * (corners[1].y - corners[0].y); lengthOfSide1 = Math.sqrt(squareOfSide1); // more method body code follows that creates and returns a // polygon connecting the Points >

You can see that, inside the method, corners is treated like an array. The method can be called either with an array or with a sequence of arguments. The code in the method body will treat the parameter as an array in either case.

You will most commonly see varargs with the printing methods; for example, this printf method:

public PrintStream printf(String format, Object. args)

allows you to print an arbitrary number of objects. It can be called like this:

System.out.printf("%s: %d, %s%n", name, idnum, address);

System.out.printf("%s: %d, %s, %s, %s%n", name, idnum, address, phone, email);

or with yet a different number of arguments.

Parameter Names

When you declare a parameter to a method or a constructor, you provide a name for that parameter. This name is used within the method body to refer to the passed-in argument.

The name of a parameter must be unique in its scope. It cannot be the same as the name of another parameter for the same method or constructor, and it cannot be the name of a local variable within the method or constructor.

A parameter can have the same name as one of the class's fields. If this is the case, the parameter is said to shadow the field. Shadowing fields can make your code difficult to read and is conventionally used only within constructors and methods that set a particular field. For example, consider the following Circle class and its setOrigin method:

The Circle class has three fields: x , y , and radius . The setOrigin method has two parameters, each of which has the same name as one of the fields. Each method parameter shadows the field that shares its name. So using the simple names x or y within the body of the method refers to the parameter, not to the field. To access the field, you must use a qualified name. This will be discussed later in this lesson in the section titled "Using the this Keyword."

Passing Primitive Data Type Arguments

Primitive arguments, such as an int or a double , are passed into methods by value. This means that any changes to the values of the parameters exist only within the scope of the method. When the method returns, the parameters are gone and any changes to them are lost. Here is an example:

public class PassPrimitiveByValue < public static void main(String[] args) < int x = 3; // invoke passMethod() with // x as argument passMethod(x); // print x to see if its // value has changed System.out.println("After invoking passMethod, x codeblock"> 
After invoking passMethod, x = 3
 
Passing Reference Data Type Arguments
 
Reference data type parameters, such as objects, are also passed into methods by value. This means that when the method returns, the passed-in reference still references the same object as before. However, the values of the object's fields can be changed in the method, if they have the proper access level.
 
For example, consider a method in an arbitrary class that moves Circle objects:
 
public void moveCircle(Circle circle, int deltaX, int deltaY) < // code to move origin of circle to x+deltaX, y+deltaY circle.setX(circle.getX() + deltaX); circle.setY(circle.getY() + deltaY); // code to assign a new reference to circle circle = new Circle(0, 0); >
 
Let the method be invoked with these arguments:
 
Inside the method, circle initially refers to myCircle . The method changes the x and y coordinates of the object that circle references (that is, myCircle ) by 23 and 56, respectively. These changes will persist when the method returns. Then circle is assigned a reference to a new Circle object with x = y = 0 . This reassignment has no permanence, however, because the reference was passed in by value and cannot change. Within the method, the object pointed to by circle has changed, but, when the method returns, myCircle still references the same Circle object as before the method was called.
 
Источник