Load xml file in java

Read an XML File using DOM Parser in Java

In this Java xml parser tutorial, learn to read XML using DOM parser. DOM parser is intended for working with XML as an object graph (a tree-like structure) in memory – the so-called “Document Object Model (DOM)“.

At first, the parser traverses the input XML file and creates DOM objects corresponding to the nodes in the XML file. These DOM objects are linked together in a tree-like structure. Once the parser is done with the parsing process, we get this tree-like DOM object structure back from it. Now we can traverse the DOM structure back and forth as we want – to get/update/delete data from it.

The other possible ways to read an XML file are using the SAX parser and StAX parser as well.

For demo purposes, we will be parsing the below XML file in all code examples.

  Lokesh Gupta India  Alex Gussin Russia  David Feezor USA  

Let’s note down some broad steps to create and use a DOM parser to parse an XML file in java.

1.1. Import dom Parser Packages

We will need to import dom parser packages first in our application.

import org.w3c.dom.*; import javax.xml.parsers.*; import java.io.*;

1.2. Create DocumentBuilder

The next step is to create the DocumentBuilder object.

DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance(); DocumentBuilder builder = factory.newDocumentBuilder();

1.3. Create Document object from XML file

Read the XML file to Document object.

Document document = builder.parse(new File( file ));

1.4. Validate Document Structure

XML validation is optional but good to have it before starting parsing.

Schema schema = null; try < String language = XMLConstants.W3C_XML_SCHEMA_NS_URI; SchemaFactory factory = SchemaFactory.newInstance(language); schema = factory.newSchema(new File(name)); >catch (Exception e) < e.printStackStrace(); >Validator validator = schema.newValidator(); validator.validate(new DOMSource(document));

1.5. Extract the Root Element

Читайте также:  Первая подстрока строки php

We can get the root element from the XML document using the below code.

Element root = document.getDocumentElement();

We can examine the XML element attributes using the below methods.

element.getAttribute("attributeName") ; //returns specific attribute element.getAttributes(); //returns a Map (table) of names/values

Child elements for a specified Node can be inquired about in the below manner.

node.getElementsByTagName("subElementName"); //returns a list of sub-elements of specified name node.getChildNodes(); //returns a list of all child nodes

2. Read XML File with DOM parser

In the below example code, we are assuming that the user is already aware of the structure of employees.xml file (its nodes and attributes). So example directly starts fetching information and starts printing it in the console. In a real-life application, we will use this information for some real purpose rather than just printing it on the console and leaving.

public static Document readXMLDocumentFromFile(String fileNameWithPath) throws Exception < //Get Document Builder DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance(); DocumentBuilder builder = factory.newDocumentBuilder(); //Build Document Document document = builder.parse(new File(fileNameWithPath)); //Normalize the XML Structure; It's just too important !! document.getDocumentElement().normalize(); return document; >

Now we can use this method to parse the XML file and verify the content.

public static void main(String[] args) throws Exception < Document document = readXMLDocumentFromFile("c:/temp/employees.xml"); //Verify XML Content //Here comes the root node Element root = document.getDocumentElement(); System.out.println(root.getNodeName()); //Get all employees NodeList nList = document.getElementsByTagName("employee"); System.out.println("============================"); for (int temp = 0; temp < nList.getLength(); temp++) < Node node = nList.item(temp); if (node.getNodeType() == Node.ELEMENT_NODE) < //Print each employee's detail Element eElement = (Element) node; System.out.println("\nEmployee id : " + eElement.getAttribute("id")); System.out.println("First Name : " + eElement.getElementsByTagName("firstName").item(0).getTextContent()); System.out.println("Last Name : " + eElement.getElementsByTagName("lastName").item(0).getTextContent()); System.out.println("Location : " + eElement.getElementsByTagName("location").item(0).getTextContent()); >> >
employees ============================ Employee id : 111 First Name : Lokesh Last Name : Gupta Location : India Employee id : 222 First Name : Alex Last Name : Gussin Location : Russia Employee id : 333 First Name : David Last Name : Feezor Location : USA

Another real-life application’s requirement might be populating the DTO objects with information fetched in the above example code. I wrote a simple program to help us understand how it can be done easily.

Читайте также:  Язык оформления документов css

Let’s say we have to populate Employee objects which are defined as below.

Now, look at the example code to populate the Employee objects list. It is just as simple as inserting a few lines in between the code, and then copying the values in DTOs instead of the console.

public static List parseXmlToPOJO(String fileName) throws Exception < Listemployees = new ArrayList(); DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance(); DocumentBuilder builder = factory.newDocumentBuilder(); Document document = builder.parse(new File(fileName)); document.getDocumentElement().normalize(); NodeList nList = document.getElementsByTagName("employee"); for (int temp = 0; temp < nList.getLength(); temp++) < Node node = nList.item(temp); if (node.getNodeType() == Node.ELEMENT_NODE) < Element eElement = (Element) node; Employee employee = new Employee(); employee.setId(Integer.parseInt(eElement.getAttribute("id"))); employee.setFirstName(eElement.getElementsByTagName("firstName").item(0).getTextContent()); employee.setLastName(eElement.getElementsByTagName("lastName").item(0).getTextContent()); employee.setLocation(eElement.getElementsByTagName("location").item(0).getTextContent()); //Add Employee to list employees.add(employee); >> return employees; >

4. Parse “unknown” XML using NamedNodeMap

The previous example shows how we can iterate over an XML document parsed with known or little know structure to you, while you are writing the code. In some cases, we may have to write the code in such a way that even if there are some differences in the assumed XML structure while coding, the program must work without failure.

Here we are iterating over all elements present in the XML document tree. we can add our knowledge and modify the code such that as soon as we get the required information while traversing the tree, we just use it.

private static void visitChildNodes(NodeList nList) < for (int temp = 0; temp < nList.getLength(); temp++) < Node node = nList.item(temp); if (node.getNodeType() == Node.ELEMENT_NODE) < System.out.println("Node Name = " + node.getNodeName() + "; Value = " + node.getTextContent()); //Check all attributes if (node.hasAttributes()) < // get attributes names and values NamedNodeMap nodeMap = node.getAttributes(); for (int i = 0; i < nodeMap.getLength(); i++) < Node tempNode = nodeMap.item(i); System.out.println("Attr name : " + tempNode.getNodeName() + "; Value wp-block-code">employees ============================ Node Name = employee; Value = Lokesh Gupta India Attr name : id; Value = 111 Node Name = firstName; Value = Lokesh Node Name = lastName; Value = Gupta Node Name = location; Value = India Node Name = employee; Value = Alex Gussin Russia Attr name : id; Value = 222 Node Name = firstName; Value = Alex Node Name = lastName; Value = Gussin Node Name = location; Value = Russia Node Name = employee; Value = David Feezor USA Attr name : id; Value = 333 Node Name = firstName; Value = David Node Name = lastName; Value = Feezor Node Name = location; Value = USA

That’s all for this good-to-know concept around Java XML DOM Parser. Drop me a comment if something is not clear OR needs more explanation.

Источник

Load xml file in java

Learn Latest Tutorials

Splunk tutorial

SPSS tutorial

Swagger tutorial

T-SQL tutorial

Tumblr tutorial

React tutorial

Regex tutorial

Reinforcement learning tutorial

R Programming tutorial

RxJS tutorial

React Native tutorial

Python Design Patterns

Python Pillow tutorial

Python Turtle tutorial

Keras tutorial

Preparation

Aptitude

Logical Reasoning

Verbal Ability

Company Interview Questions

Artificial Intelligence

AWS Tutorial

Selenium tutorial

Cloud Computing

Hadoop tutorial

ReactJS Tutorial

Data Science Tutorial

Angular 7 Tutorial

Blockchain Tutorial

Git Tutorial

Machine Learning Tutorial

DevOps Tutorial

B.Tech / MCA

DBMS tutorial

Data Structures tutorial

DAA tutorial

Operating System

Computer Network tutorial

Compiler Design tutorial

Computer Organization and Architecture

Discrete Mathematics Tutorial

Ethical Hacking

Computer Graphics Tutorial

Software Engineering

html tutorial

Cyber Security tutorial

Automata Tutorial

C Language tutorial

C++ tutorial

Java tutorial

.Net Framework tutorial

Python tutorial

List of Programs

Control Systems tutorial

Data Mining Tutorial

Data Warehouse Tutorial

Javatpoint Services

JavaTpoint offers too many high quality services. Mail us on h[email protected], to get more information about given services.

  • Website Designing
  • Website Development
  • Java Development
  • PHP Development
  • WordPress
  • Graphic Designing
  • Logo
  • Digital Marketing
  • On Page and Off Page SEO
  • PPC
  • Content Development
  • Corporate Training
  • Classroom and Online Training
  • Data Entry

Training For College Campus

JavaTpoint offers college campus training on Core Java, Advance Java, .Net, Android, Hadoop, PHP, Web Technology and Python. Please mail your requirement at [email protected].
Duration: 1 week to 2 week

Like/Subscribe us for latest updates or newsletter RSS Feed Subscribe to Get Email Alerts Facebook Page Twitter Page YouTube Blog Page

Источник

Оцените статью