Java string format escaping

Escaping formatting characters in java String.format

Solution 2: You can first is replace escaped symbols and then replace escaped slashes with single slashes: We can do this by finding occurrences of two slash pairs: Combine this with the symbol you want to replace (for example ): Then we escape this string for java: Now you can write a helper method for this regex which keeps the first group and replaces the second group: For example. THe reason I need to do this is that I’m building up a string that will later have more info inserted into it.

Escaping formatting characters in java String.format

This question is pretty much the same as this .Net question exept for java.

How do you escape the %1$ characters in a java String.format ?

THe reason I need to do this is that I’m building up a string that will later have more info inserted into it. I’ve thought of having one of the args just be «%1$» but that doesn’t seem to be very elegant?

sorry if this is obvious my java is a tad rusty.

You can just double up the %

Either you can use the proposal of Draemon, either you can also have a look at java.text.messageformat class that has more powerfull formatting abilities than String.format()

How to escape a string to be passed into DecimalFormat, Special characters, on the other hand, stand for other characters, strings, or classes of characters. They must be quoted, unless noted otherwise, if they are to appear in the prefix or suffix as literals. ‘ can be used to quote special characters in a prefix or suffix, for example, «‘#’#» formats 123 to «#123».

Java — Properly format a String given escape sequences and escape characters

Given new line (\n), tab (\t) and an escape character \ how can I given a string format it properly so it deals with these escape sequences and escape characters properly. Example 1:

So in this case \\t is escaped to just \t and \t is formatted with a tab

I tried brute-forcing a solution but it didn’t work as I am having problems delimiting tabs and spaces with a backslash infront.

String v= ". " //v for value v = v.replace("\\\"","\""); v = v.replace("\\\\","\\"); v = v.replace("\\t", " "); v = v.replace("\\n", "\n"); v = v.replace("\\\t", "\\t"); v = v.replace("\\\n", "\\n"); 

If I ran that code through the first example it would give:

looks like the one «brute force» combination you didn’t try is correct

reading «replace all < backslash > < t >combinations with < tab >«

String them all together to get

(there’s no need to replace \ by itself)

You can first is replace escaped symbols and then replace escaped slashes with single slashes:

We can do this by finding occurrences of two slash pairs:

(^|[^\\])(\\\\)* - (^|[^\\]) is the start of the string or not a slash - (\\\\)* is slash pairs 

Combine this with the symbol you want to replace (for example \n ):

Then we escape this string for java:

Now you can write a helper method for this regex which keeps the first group $1 and replaces the second group:

public static String replaceEscapedChar( final String source, final char escaped, final char actual )

For example. The following produces:

replaceEscapedChar("Test\\\\\\nTest\\\\n", 'n', '\n'); Test\\ Test\\n 

PS: You can also remove the quotes afterwards by writing:

How to escape DecimalFormat pattern symbol in java, I want to format the number with DecimalFormat pattern symbol. Any idea to do?? Ex: ### 123 dollars and 00 cents ### where 123 is need to formatted using DecimalFormat.format method. In C#, it is possible with escape(«\») character. Is there any similar way in java?

Escape % symbol in a java string to apply String.format

In my project (Java/Play framework) I have an error handling routing that checks the response from a web service if the response is an error code, we display the corresponding error message saying what was the problem with the user input, the service checks user input validity.

When the user enter an % symbol, this logic breaks because the error display logic uses

String.format(message, messageArgs); 

Which interpolates the messageArgs intro the message String where it finds an %, and if the messageArgs contains an % as well I get an exception.

I need to sanitize, escape or otherwise remove the % from the user inputs, before displaying the message.

message: The requested email address %s is invalid messageArgs: orlybg%@gmail.com

Any advice on how to do this in Java in the simplest, shortest way?

here’s a part of the error log

 java.util.UnknownFormatConversionException: Conversion = 'i' at java.util.Formatter$FormatSpecifier.conversion(Formatter.java:2646) at java.util.Formatter$FormatSpecifier.(Formatter.java:2675) at java.util.Formatter.parse(Formatter.java:2528) at java.util.Formatter.format(Formatter.java:2469) at java.util.Formatter.format(Formatter.java:2423) at java.lang.String.format(String.java:2797) at controllers.api.PublicAPI.renderAPIError(PublicAPI.java:176) at controllers.api.DeviceAPI.setEmailAddress(DeviceAPI.java:736) at play.mvc.ActionInvoker.invokeWithContinuation(ActionInvoker.java:557) at play.mvc.ActionInvoker.invoke(ActionInvoker.java:508) at play.mvc.ActionInvoker.invokeControllerMethod(ActionInvoker.java:484) at play.mvc.ActionInvoker.invokeControllerMethod(ActionInvoker.java:479) at play.mvc.ActionInvoker.invoke(ActionInvoker.java:161) at Invocation.HTTP Request(Play!) 

In message String, the % sign is escaped with another %. So you will need to double it up: %%
For example: «Bla bla %i bla» -> «Bla bla %%i bla»
In messageArgs String, there is no problem with the % sign and you don’t need to escape it

Use %% in the formatter string when you need to print string % :

String.format("sendOneSuccessCountRate: %7.2f%%" ,sendOneSuccessCountRate //0.95 ); 

If you receive java.util.UnknownFormatConversionException: Conversion = ‘i’ most possibly you use %i in your message trying to format an integer, this is not correct. You must use %d to format the deciamal integer. Full supported conversion specification could be found here.

Format String in Java with printf(), format(), Formatter, To print special characters (such as «) directly we need to escape its effects first, and in Java that means prefixing it with a backslash ( \ ). To legally print a quotation mark in Java we would do the following: System.out.printf ( «\»» );

How to escape dot character using String.format

Using Java 8, I would like to get this code block :

System.out.println(String.format("Hello %.", "world")); 

Exception in thread "main" java.util.UnknownFormatConversionException: Conversion = '.' at java.util.Formatter.checkText(Formatter.java:2579) at java.util.Formatter.parse(Formatter.java:2565) at java.util.Formatter.format(Formatter.java:2501) at java.util.Formatter.format(Formatter.java:2455) at java.lang.String.format(String.java:2940) 

How could I escape this dot character, which seems to have a special meaning ?

System.out.println(String.format(«Hello %s.», «world»));

Java — Formatting print statements with escape, I’m having an issue getting my columns to line up correctly. All I have to do is take input from the user and then print ASCII character values for letters in one column, ASCII values for numbers i

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Escape percent sign in String’s format method in java

In this post, we will see how to escape Percent sign in String’s format() method in java.

Escape Percent Sign in String’s Format Method in Java

String’s format() method uses percent sign( % ) as prefix of format specifier.
For example:
To use number in String’s format() method, we use %d , but what if you actually want to use percent sign in the String.

If you want to escape percent sign in String’s format method, you can use % twice ( %% ).

Let’s see with the help of example:

As you can see, we have used %% to escape percent symbol in 10% .

Further reading:

How to escape double quotes in String in java

Print double quotes in java

Escape Percent Sign in printf() Method in Java

You can apply same logic in printf method to print percent sign using System.out.printf() method.

That’s all about How to escape percent sign in String’s format method in java.

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