Java http multipart parse

Содержание

(Java) Parse Multipart Binary Http Response
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Library for Parsing multipart File Upload with Java
Library for Parsing multipart File Upload with Java

(Java) Parse Multipart Binary Http Response

This example demonstrates how to parse an HTTP response that is multipart and contains a binary file, such as a .zip or .pdf.

Chilkat Java Downloads

import com.chilkatsoft.*; public class ChilkatExample < static < try < System.loadLibrary("chilkat"); > catch (UnsatisfiedLinkError e) < System.err.println("Native code library failed to load.\n" + e); System.exit(1); > > public static void main(String argv[]) < // This example requires the Chilkat API to have been previously unlocked. // See Global Unlock Sample for sample code. boolean success; CkHttp http = new CkHttp(); CkHttpRequest req = new CkHttpRequest(); // . // Insert code here to construct some kind of HTTP request. // this example is to show how to parse a particular kind of response. // . // . // Send the request (whatever it may be in your case) to get the HTTP response object. CkHttpResponse resp = http.SynchronousRequest("www.somedomain.com",443,true,req); if (http.get_LastMethodSuccess() != true) < System.out.println(http.lastErrorText()); return; > // Get the response body (which is expected to be binary) CkBinData respBody = new CkBinData(); resp.GetBodyBd(respBody); // For this example, the response body contains something like this: // ------=_Part_21302_2029949381.1547401515443 // Content-Type: application/xop+xml; charset=UTF-8; type="text/xml" // Content-Transfer-Encoding: 8bit // Content-ID: // // .  // ------=_Part_21302_2029949381.1547401515443 // Content-Type: application/octet-stream // Content-Transfer-Encoding: binary // Content-Id: // // BINARY_CONTENT_HERE. // // ------=_Part_21302_2029949381.1547401515443-- // // Load it into a Chilkat MIME object. CkMime mime = new CkMime(); success = mime.LoadMimeBd(respBody); if (success != true) < System.out.println(mime.lastErrorText()); return; > int numParts = mime.get_NumParts(); if (numParts < 2) < System.out.println("Expected multipart MIME with at least 2 sub-parts."); return; > // Get the 1st sub-part, which is the XML. CkMime part0 = mime.GetPart(0); // Should be OK because we checked NumParts above.. String xmlStr = part0.getBodyDecoded(); System.out.println(xmlStr); System.out.println("----"); // Save the 2nd part to a file. (It is a .zip file in our test case..) CkMime part1 = mime.GetPart(1); success = part1.SaveBody("qa_output/attachedZip.zip"); // Alternatively, we could extract the binary data to a BinData and use elsewhere.. CkBinData zipData = new CkBinData(); success = part1.GetBodyBd(zipData); success = zipData.WriteFile("qa_output/attachedZip_again.zip"); System.out.println("OK."); > >

Источник

Library for Parsing multipart File Upload with Java

One of the most convinient ways to upload files from the Web Browser to the server is by using file inputs in HTML forms.

Many web servers come with preconfigured modules for parsing this data on the server-side. However, sometimes, your HTTP server of choice might not offer such a module and you are left with the task of parsing the data the browser submits to the server yourself.

I specifically encountered this problem when working with a Netty-based server.

The form will most likely submit the files to your server as part of a multipart/form-data request. These are not that straightforward to parse. Thankfully, there is the library Apache Commons FileUpload which can be used for this purpose.

Unfortunately, processing some arbitrary binary data with this library is not very straightforward. This has motivated me to write a small library — delight-fileupload — which wraps Commons FileUpload and makes parsing multipart form data a breeze. (This library is part of the Java Delight Suite).

Just include the library and let it parse your data as follows:

FileItemIterator iterator = FileUpload.parse(data, contentType);

Where data is a binary array of the data you received from the client and contentType is the content type send via HTTP header.

Then you can iterate through all the files submitted in the form as follows:

You can find the library on GitHub. It is on Maven Central. Just add the following dependency to your Java, Scala etc. application and you are good to go:

org.javadelight delight-fileupload 0.0.3

You can also check for the newest version on the JCenter repostiory.

I hope this is helpful. If you have any comments or suggestions, leave a comment here or raise an issue on the javadelight-fileupload GitHub project.

Insights for developing lean applications with ease 😎 and my musings on life and leadership ✍.

Источник

Library for Parsing multipart File Upload with Java

One of the most convinient ways to upload files from the Web Browser to the server is by using file inputs in HTML forms.

I specifically encountered this problem when working with a Netty-based server.

Just include the library and let it parse your data as follows:

FileItemIterator iterator = FileUpload.parse(data, contentType);

Where data is a binary array of the data you received from the client and contentType is the content type send via HTTP header.

Then you can iterate through all the files submitted in the form as follows:

You can find the library on GitHub. It is on Maven Central. Just add the following dependency to your Java, Scala etc. application and you are good to go:

org.javadelight delight-fileupload 0.0.3

You can also check for the newest version on the JCenter repostiory.

I hope this is helpful. If you have any comments or suggestions, leave a comment here or raise an issue on the javadelight-fileupload GitHub project.

Insights for developing lean applications with ease 😎 and my musings on life and leadership ✍.

Источник