Getting filename without extension java

How to get name of File object without its extension in Java? [duplicate]

– Solution 1: I usually use this solution described in other post:Solution 2: You can do it like this: or you can use the apache.commons.io.FilenameUtils: Solution 3: You could use the class to get the file name: Using a object has numerous benefits, including the ability to test the file exists: You also need to check the file has an extension before you try and strip it: Solution 4: You can call the method that returns the name of the file as String. This code will do the work of removing the extension and printing name of file: If you are ok with standard libraries then use Apache Common as it has ready-made method for that.

How to get the filename without the extension in Java?

Can anyone tell me how to get the filename without the extension? Example:

fileNameWithExt = "test.xml"; fileNameWithOutExt = "test"; 

If you, like me, would rather use some library code where they probably have thought of all special cases, such as what happens if you pass in null or dots in the path but not in the filename, you can use the following:

import org.apache.commons.io.FilenameUtils; String fileNameWithOutExt = FilenameUtils.removeExtension(fileNameWithExt); 

The easiest way is to use a regular expression.

fileNameWithOutExt = "test.xml".replaceFirst("[.][^.]+$", ""); 

The above expression will remove the last dot followed by one or more characters. Here’s a basic unit test.

Here is the consolidated list order by my preference.

Using apache commons

import org.apache.commons.io.FilenameUtils; String fileNameWithoutExt = FilenameUtils.getBaseName(fileName); OR String fileNameWithOutExt = FilenameUtils.removeExtension(fileName); 

Using Google Guava (If u already using it)

import com.google.common.io.Files; String fileNameWithOutExt = Files.getNameWithoutExtension(fileName); 

Or using Core Java

String fileName = file.getName(); int pos = fileName.lastIndexOf("."); if (pos > 0 && pos < (fileName.length() - 1)) < // If '.' is not the first or last character. fileName = fileName.substring(0, pos); >

if (fileName.indexOf(".") > 0) < return fileName.substring(0, fileName.lastIndexOf(".")); >else

private static final Pattern ext = Pattern.compile("(?

Liferay API

import com.liferay.portal.kernel.util.FileUtil; String fileName = FileUtil.stripExtension(file.getName()); 

See the following test program:

public class javatemp < static String stripExtension (String str) < // Handle null case specially. if (str == null) return null; // Get position of last '.'. int pos = str.lastIndexOf("."); // If there wasn't any '.' just return the string as is. if (pos == -1) return str; // Otherwise return the string, up to the dot. return str.substring(0, pos); >public static void main(String[] args) < System.out.println ("test.xml ->" + stripExtension ("test.xml")); System.out.println ("test.2.xml -> " + stripExtension ("test.2.xml")); System.out.println ("test -> " + stripExtension ("test")); System.out.println ("test. -> " + stripExtension ("test.")); > > 

test.xml -> test test.2.xml -> test.2 test -> test test. -> test 

How to get the filename without the extension in Java?, Add a comment. 2. You can use java split function to split the filename from the extension, if you are sure there is only one dot in the filename which for extension. File filename = new File (‘test.txt’); File.getName ().split (» [.]»); so the split [0] will return «test» and split [1] will return «txt». Code sampleimport org.apache.commons.io.FilenameUtils;String fileNameWithOutExt = FilenameUtils.removeExtension(fileNameWithExt);Feedback

How to get name of File object without its extension in Java? [duplicate]

I am trying to get name of a File object without its extension, e.g. getting «vegetation» when the filename is «vegetation.txt.» I have tried implementing this code:

openFile = fileChooser.getSelectedFile(); String[] tokens = openFile.getName().split("."); String name = tokens[0]; 

Unfortunately, it returns a null object. There is a problem just in the defining the String object, I guess, because the method getName() works correctly; it gives me the name of the file with its extension.

If you want to implement this yourself, try this:

String name = file.getName(); int pos = name.lastIndexOf("."); if (pos > 0)

(This variation doesn’t leave you with an empty string for an input filename like «.txt». If you want the string to be empty in that case, change > 0 to >= 0 .)

You could replace the if statement with an assignment using a conditional expression, if you thought it made your code more readable; see @Steven’s answer for example. (I don’t think it does . but it is a matter of opinion.)

It is arguably a better idea to use an implementation that someone else has written and tested. Apache FilenameUtils is a good choice; see @slachnick’s Answer, and also the linked Q&A.

If you don’t want to write this code yourself you could use Apache’s filenameutils.

FilenameUtils.getBaseName(openFile.getName()); 

This will return the filename minus the path and extension.

I prefer to chop off before the last index of «.» to be the filename. This way a file name: hello.test.txt is just hello.test

int pos = filename.lastIndexOf("."); String justName = pos > 0 ? filename.substring(0, pos) : filename; 

You need to handle there being no extension too.

String#split takes a regex. «.» matches any character, so you’re getting an array of empty strings — one for each spot in between each pair of characters.

How to get name of File object without its extension in, (This variation doesn’t leave you with an empty string for an input filename like «.txt». If you want the string to be empty in that case, change > 0 to >= 0 .) You could replace the if statement with an assignment using a conditional expression, if you thought it made your code more readable; see @Steven’s answer for example.

Java — Getting file name without extension from a folder

I’m using this code to get the absolute path of files inside a folder

public void addFiles(String fileFolder) < ArrayListfiles = new ArrayList(); fileOp.getFiles(fileFolder, files); > 

But I want to get only the file name of the files (without extension). How can I do this?

i don’t think such a method exists. you can get the filename and get the last index of . and truncate the content after that and get the last index of File.separator and remove contents before that.

or you can use FilenameUtils from apache commons IO and use the following

This code will do the work of removing the extension and printing name of file:

 public static void main(String[] args) < String path = "C:\\Users\\abc\\some"; File folder = new File(path); File[] files = folder.listFiles(); String fileName; int lastPeriodPos; for (int i = 0; i < files.length; i++) < if (files[i].isFile()) < fileName = files[i].getName(); lastPeriodPos = fileName.lastIndexOf('.'); if (lastPeriodPos >0) fileName = fileName.substring(0, lastPeriodPos); System.out.println("File name is " + fileName); > > > 

If you are ok with standard libraries then use Apache Common as it has ready-made method for that.

There’s a really good way to do this — you can use FilenameUtils.removeExtension.

String filePath = "/storage/emulated/0/Android/data/myAppPackageName/files/Pictures/JPEG_20180813_124701_-894962406.jpg" String nameWithoutExtension = Files.getNameWithoutExtension(filePath); 

Java — Getting file name without extension from a folder, i don’t think such a method exists. you can get the filename and get the last index of . and truncate the content after that and get the last index of File.separator and remove contents before that. you got your file name. or you can use FilenameUtils from apache commons IO and use the following . …

Get filename without extension from full path [duplicate]

I am making a program to store data from excel files in database. I would like the user to give in console the full path of the file and after the program to take only the file name to continue.

The code for loading the full path is:

String strfullPath = ""; Scanner scanner = new Scanner(System.in); System.out.println("Please enter the fullpath of the file"); strfullPath = scanner.nextLine(); String file = strfullPath.substring(strfullPath.lastIndexOf('/') + 1); System.out.println(file.substring(0, file.indexOf('.'))); 

After that I would like to have: String filename = .

The full path that the user would type would be like this: C:\\Users\\myfiles\\Documents\\test9.xls

The filename that I would create would take only the name without the .xls ! Could anyone help me how I would do this?

How i would do it if i would like to take as filename «test9.xls» ? –

I usually use this solution described in other post:

import org.apache.commons.io.FilenameUtils; String basename = FilenameUtils.getBaseName(fileName); 

String fname = file.getName(); int pos = fname.lastIndexOf("."); if (pos > 0)

or you can use the apache.commons.io.FilenameUtils:

String fileNameWithOutExt = FilenameUtils.removeExtension(fileNameWithExt); 

You could use the File class to get the file name:

File userFile = new File(strfullPath); String filename = userFile.getName(); 

Using a File object has numerous benefits, including the ability to test the file exists:

You also need to check the file has an extension before you try and strip it:

You can call the file.getName() method that returns the name of the file as String. Then you cut the extension.

String fileName = file.getName(); fileName = fileName.substring(0, fileName.lastIndexOf(".")+1); 

Java — Get filename without extension from full path, You could use the File class to get the file name: File userFile = new File(strfullPath); String filename = userFile.getName(); Using a File object has numerous benefits, including the ability to test the file exists:

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How to Get the Filename Without the Extension in Java

How to get the filename without the extension in Java?

If you, like me, would rather use some library code where they probably have thought of all special cases, such as what happens if you pass in null or dots in the path but not in the filename, you can use the following:

import org.apache.commons.io.FilenameUtils;
String fileNameWithOutExt = FilenameUtils.removeExtension(fileNameWithExt);

How to get name of File object without its extension in Java?

If you want to implement this yourself, try this:

String name = file.getName();
int pos = name.lastIndexOf(".");
if (pos > 0) name = name.substring(0, pos);
>

(This variation doesn’t leave you with an empty string for an input filename like «.txt». If you want the string to be empty in that case, change > 0 to >= 0 .)

You could replace the if statement with an assignment using a conditional expression, if you thought it made your code more readable; see @Steven’s answer for example. (I don’t think it does . but it is a matter of opinion.)

It is arguably a better idea to use an implementation that someone else has written and tested. Apache FilenameUtils is a good choice; see @slachnick’s Answer, and also the linked Q&A.

Java — Getting file name without extension from a folder

This code will do the work of removing the extension and printing name of file:

 public static void main(String[] args) String path = "C:\\Users\\abc\\some"; 
File folder = new File(path); 
File[] files = folder.listFiles(); 
String fileName; 
int lastPeriodPos; 
for (int i = 0; i < files.length; i++) if (files[i].isFile()) fileName = files[i].getName(); 
lastPeriodPos = fileName.lastIndexOf('.'); 
if (lastPeriodPos > 0) 
fileName = fileName.substring(0, lastPeriodPos); 
System.out.println("File name is " + fileName); 
> 
> 
>

If you are ok with standard libraries then use Apache Common as it has ready-made method for that.

How do I get the file extension of a file in Java?

In this case, use FilenameUtils.getExtension from Apache Commons IO

Here is an example of how to use it (you may specify either full path or just file name):

import org.apache.commons.io.FilenameUtils;

// . 

String ext1 = FilenameUtils.getExtension("/path/to/file/foo.txt"); // returns "txt"
String ext2 = FilenameUtils.getExtension("bar.exe"); // returns "exe"

implementation 'commons-io:commons-io:2.6'

implementation("commons-io:commons-io:2.6")

How to get only filename without .mp3 and .mp4 extension in android?

Try this way to get filename without extension:-

if (fileName.indexOf(".") > 0) 
fileName = fileName.substring(0, fileName.lastIndexOf("."));

How to trim a file extension from a String in JavaScript?

If you know the length of the extension, you can use x.slice(0, -4) (where 4 is the three characters of the extension and the dot).

If you don’t know the length @John Hartsock regex would be the right approach.

If you’d rather not use regular expressions, you can try this (less performant):

filename.split('.').slice(0, -1).join('.')

Note that it will fail on files without extension.

Regex to get filename with or without extension from a path

The following regex will match desired parts:

• ^ Match start of the line
• (?: Start of a non-capturing group

but if you are dealing with a multi-line input string and need a bit faster regex try this one instead (with m flag on) :

See live demo here

Filename would be captured in the first capturing group.

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