Append takes exactly one argument 2 given python

Has convertido dos argumentos:

The use of brackets combines them into a SINGLE set.

TypeError: append() takes exactly one argument (2 given), Remplaza: lista3.append(columna,fil). Por: lista3.append([columna,fil]). Y ya esta: Has convertido dos argumentos:.

How to fix append() error after passing a list

Attempting to append the list to itself results in an error stating that it requires only one argument. I have experimented with saving the divided line in different variables.

 testfile = open(r'''C:\Users\shawa\Desktop\sampleg102.txt''' ,'r') print(testfile) word=list for line in testfile: line = line.lstrip() word = word.append([1]) print(word) 

E:\vscode.source> python -u "e:\vscode.source\python\countingWords.py" Traceback (most recent call last): File "e:\vscode.source\python\countingWords.py", line 7, in word = word.append([1]) TypeError: append() takes exactly one argument (0 given) 

To illustrate the initial error, observe the following:

>>> list >>> word = list >>> word >>> word = list() >>> word 

Currently, you have designated only one name, list , for word . To instantiate the list, you must invoke the list constructor. The list.append() function alters the list directly, and its return value, None , does not require reassignment.

word = list() # word = '' works too for line in testfile: line = line.lstrip() word.append([1]) print(word) 

Currently, your code generates a list comprising sub-lists, each containing only 1s. If your intention was to add the file's lines, then employ the following method.

Using the literal syntax of an empty list, denoted by [] , is more preferable than calling list() to create a list, as it makes it easier to understand what is being created.

The keyword word=list. list is not what you need, instead use list() which creates an instance of a list.

If you intend to add a line to a list, make sure to perform this action. Currently, your code only adds [1] to the list named "word".

testfile = open(r'''C:\Users\shawa\Desktop\sampleg102.txt''' ,'r') print(testfile) word=list() for line in testfile: line = line.lstrip() word.append(1) #or word.append(line[1]) according to use case print(word) 

TypeError: count() takes exactly one argument, I'm new to Python and Django, and I modified this code from a tutorial. I'm getting TypeError: count() takes exactly one argument (0 given) when

TypeError: list.append() takes exactly one argument (2 given)

def PonerFecha(): year=int(input('Digite el año: ')) month=int(input('Digite el mes: ')) day=int(input('Digite el dia: ')) FechaNueva=(year,month,day) for j in range (len(matchs)-1): if matchs[j] 

I require specific data to be stored in the list. While the date function works properly, I am encountering an error with the other function related to goals. I am unsure how to fix it and have attempted various methods, none of which have been successful. Thank you. The data is saved in the following manner.

Pero necesito que se guarden asi:

To obtain both pieces of information in a single tuple, simply add them together. This will merge their elements into a single tuple.

 . if opcion==1: matchs.append(PonerFecha()+EntrarDatos()) print(matchs) 

Your block has an error because you're utilizing the comparison operator ( == ) instead of the assignment operator ( = ) ( except ). To avoid this, I suggest changing it to ( continue ) which will allow the loop to restart and prompt the user for the information again ( opcion==-1 ).

The error message indicates that you have provided two arguments for the list.append method, which only requires one. To add items to a list, you can use the append method, but only one item at a time. Therefore, you need to modify the line.

matchs.append(PonerFecha(),EntrarDatos()) 

matchs.append(PonerFecha()) matchs.append(EntrarDatos()) 

By doing so, you are adding the data to the matches list.

Cant figure out why 'TypeError: function takes exactly 1 argument (2, Your executescript expects one string query to be executed but you are providing 2 parameters the query and variables.

TypeError in python for loop

While practicing For loop in Python, I encountered a TypeError indicating that the append function only accepts one argument, whereas I provided two.

pair_1 = [] for num1 in range(2,10): for num2 in range(3,11): pair_1.append(num1, num2) print(pair_1) 

The stack trace explicitly states it.

You are passing two values as arguments to append() which only accepts one.

You might want something like this:

pair_1 = [] for num1 in range(2,10): for num2 in range(3,11): pair_1.append([num1, num2]) print(pair_1) 

I'm uncertain about your goals, but this is what has been produced.

[[2, 3], [2, 4], [2, 5], [2, 6], [2, 7], [2, 8], [2, 9], [2, 10], [3, 3], [3, 4], [3, 5], [3, 6], [3, 7], [3, 8], [3, 9], [3, 10], [4, 3], [4, 4], [4, 5], [4, 6], [4, 7], [4, 8], [4, 9], [4, 10], [5, 3], [5, 4], [5, 5], [5, 6], [5, 7], [5, 8], [5, 9], [5, 10], [6, 3], [6, 4], [6, 5], [6, 6], [6, 7], [6, 8], [6, 9], [6, 10], [7, 3], [7, 4], [7, 5], [7, 6], [7, 7], [7, 8], [7, 9], [7, 10], [8, 3], [8, 4], [8, 5], [8, 6], [8, 7], [8, 8], [8, 9], [8, 10], [9, 3], [9, 4], [9, 5], [9, 6], [9, 7], [9, 8], [9, 9], [9, 10]] 

Instead of using pair_1.extend() , you will end up with a lengthy list that includes duplicates. Additionally, I fail to see how 'pair' is relevant in this context.

The sole argument for the append function of a list in Python is an iterable.

Two arguments, namely num1 and num2 , are being provided.

You may be attempting to perform a similar task.

pair_1 = [] for num1 in range(2,10): for num2 in range(3,11): pair_1.append([num1, num2]) print(pair_1) 

Perhaps you are attempting to perform a task similar to this.

pair_1 = [] for num1 in range(2,10): for num2 in range(3,11): pair_1.extend([num1, num2]) print(pair_1) 

The error message indicates that you can only use the append method to add one element to a list. Therefore, your current call, referenced as pair_1.append(num1, num2) , is incorrect. To fix this, you need to call the method twice.

The expected result should be an integer array, represented as shown below: [2, 3, 2, 4, 2, 5, . ]

To store pairs, you have two options. The first one is to use a 2D list, which can be achieved by using pair_1.append([num1, num2]) , a list of lists. Alternatively, you can use pair_1.append((num1, num2)) , which is a list of tuples.

The list can be modified using the append() method which adds a single element to the end of the list. Attempting to add more than one element using this method will result in an error.

Your code offers a multitude of possibilities.

pair_1 = [] for num1 in range(2,10): for num2 in range(3,11): pair_1.append(num1) pair_1.append(num2) print(pair_1) 

pair_1 = [] for num1 in range(2,10): for num2 in range(3,11): pair_1.extend([num1,num2]) print(pair_1) 

pair_1 = [] for num1 in range(2,10): for num2 in range(3,11): pair_1.extend((num1,num2)) print(pair_1) 

The outcome will be identical, regardless of whether you choose Option 1, 2, or 3.

[2, 3, 2, 4, 2, 5, 2, 6, 2, 7, 2, 8, 2, 9, 2, 10, 3, 3, 3, 4, 3, 5, 3, 6, 3, 7, 3, 8, 3, 9, 3, 10, 4, 3, 4, 4, 4, 5, 4, 6, 4, 7, 4, 8, 4, 9, 4, 10, 5, 3, 5, 4, 5, 5, 5, 6, 5, 7, 5, 8, 5, 9, 5, 10, 6, 3, 6, 4, 6, 5, 6, 6, 6, 7, 6, 8, 6, 9, 6, 10, 7, 3, 7, 4, 7, 5, 7, 6, 7, 7, 7, 8, 7, 9, 7, 10, 8, 3, 8, 4, 8, 5, 8, 6, 8, 7, 8, 8, 8, 9, 8, 10, 9, 3, 9, 4, 9, 5, 9, 6, 9, 7, 9, 8, 9, 9, 9, 10] 

pair_1 = [] for num1 in range(2,10): for num2 in range(3,11): pair_1.append([num1,num2]) print(pair_1) 

[[2, 3], [2, 4], [2, 5], [2, 6], [2, 7], [2, 8], [2, 9], [2, 10], [3, 3], [3, 4], [3, 5], [3, 6], [3, 7], [3, 8], [3, 9], [3, 10], [4, 3], [4, 4], [4, 5], [4, 6], [4, 7], [4, 8], [4, 9], [4, 10], [5, 3], [5, 4], [5, 5], [5, 6], [5, 7], [5, 8], [5, 9], [5, 10], [6, 3], [6, 4], [6, 5], [6, 6], [6, 7], [6, 8], [6, 9], [6, 10], [7, 3], [7, 4], [7, 5], [7, 6], [7, 7], [7, 8], [7, 9], [7, 10], [8, 3], [8, 4], [8, 5], [8, 6], [8, 7], [8, 8], [8, 9], [8, 10], [9, 3], [9, 4], [9, 5], [9, 6], [9, 7], [9, 8], [9, 9], [9, 10]] 

pair_1 = [] for num1 in range(2,10): for num2 in range(3,11): pair_1.append((num1,num2)) print(pair_1) 

[(2, 3), (2, 4), (2, 5), (2, 6), (2, 7), (2, 8), (2, 9), (2, 10), (3, 3), (3, 4), (3, 5), (3, 6), (3, 7), (3, 8), (3, 9), (3, 10), (4, 3), (4, 4), (4, 5), (4, 6), (4, 7), (4, 8), (4, 9), (4, 10), (5, 3), (5, 4), (5, 5), (5, 6), (5, 7), (5, 8), (5, 9), (5, 10), (6, 3), (6, 4), (6, 5), (6, 6), (6, 7), (6, 8), (6, 9), (6, 10), (7, 3), (7, 4), (7, 5), (7, 6), (7, 7), (7, 8), (7, 9), (7, 10), (8, 3), (8, 4), (8, 5), (8, 6), (8, 7), (8, 8), (8, 9), (8, 10), (9, 3), (9, 4), (9, 5), (9, 6), (9, 7), (9, 8), (9, 9), (9, 10)] 

Append() and extend() in Python, Syntax: list_name.append('value') It takes only one argument. This function appends the incoming element to the end of the list as a single

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Как передать кортеж в качестве аргумента в Python?

@Artsiom Rudzenka - Это руководство опасно 🙁 Мало того, что в нем есть ошибки, такие как смешивание списков и кортежей, оно показывает глупые вещи, такие как окончание строк ; по какой-то причине.

@viraptor да, вы правы, всегда лучше использовать официальный учебник по питону : docs.python.org/tutorial/…

Более ранние версии Python автоматически преобразовывали синтаксис append (arg, . ) в append ((arg, . )). Они вынули это, потому что это добавило беспорядок. Старые книги показали бы ваш пример как работающий. Вот почему лучше всего проверить документацию на сайте Python.org или в вашем установленном дистрибутиве Python.

4 ответа

Скобки с запятой создают кортеж, если только он не содержит список аргументов.

() # this is a 0-length tuple (1,) # this is a tuple containing "1" 1, # this is a tuple containing "1" (1) # this is number one - it exactly the same as: 1 # also number one (1,2) # tuple with 2 elements 1,2 # tuple with 2 elements 

Аналогичный эффект происходит с кортежем длины 0-:

Стоит прямо указать, что (1) НЕ является кортежем. Пара скобок в этом случае анализируется для других значений синтаксиса (для порядка и приоритета в математических оценках?). Синтаксис отличается от [1] где это список.

Это потому, что это не кортеж, это два аргумента метода add . Если вы хотите дать ему один аргумент, который является кортежем, сам аргумент должен быть (3, 'three') :

Python 2.6.5 (r265:79063, Apr 16 2010, 13:09:56) [GCC 4.4.3] on linux2 Type "help", "copyright", "credits" or "license" for more information. >>> li = [] >>> li.append(3, 'three') Traceback (most recent call last): File "", line 1, in TypeError: append() takes exactly one argument (2 given) >>> li.append( (3,'three') ) >>> li [(3, 'three')] >>> 

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