Advanced calculator in java

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scientific-calculator

Here are 37 public repositories matching this topic.

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WarpPI Calculator, Step-by-step algebra calculator for Raspberry Pi. (abandoned project)

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A scientific calculator program that gets infix expressions from input, converts them to postfix and prefix notation, and shows the result by evaluating the postfix expression.

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An Android application of a basic scientific calculator

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RupamMukherjee492 / Scientific_Calculator_Android_App

I developed a Scientific Calculator Android app, which is a Scientific Calculator Android app is a mobile application designed to provide users with advanced mathematical functions and calculations. The app is designed to help users perform complex calculations quickly and easily.

iam-debanjan007 / Terminal-Scientific-Calculator

Terminal based Scientific calculator in java

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Flexible Android Calculator

kshitiz1007 / Calculator

It is a calculator app build on android platform

aratheunseen / java-scientific-calculator-gui

This is a basic scientific calculator created in Java and Java Swing.

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advanced calculator. implementing multiple operands

Need a way to finish my ‘advanced’ calculator. i’ve been brainstorming with loops but im confusing myself. any ideas on how to implement the operands to the numbers without just nesting a bunch of if statements and hard coding through all of that.

public static void main(String[] args) < Scanner scan = new Scanner(System.in); System.out.println("welcome to your personal calculator. is your problem simple or advanced(multiple calculations)\n" + "Type 1 for simple or 2 for advanced"); int choice = scan.nextInt(); if(choice == 1)< System.out.println("Simple equation"); System.out.println("Enter the first number"); int firstnum = scan.nextInt(); System.out.println("Enter the second number"); int secondnum = scan.nextInt(); System.out.println("are you adding, subtracting multiplying or dividing? ENTER +,*,-, or /"); String operand = scan.next(); if(operand.equals("+"))< int solution = firstnum + secondnum; System.out.println(firstnum + operand + secondnum + "=" + solution); >else if (operand.equals("*")) < int solution = firstnum * secondnum; System.out.println(firstnum + operand + secondnum + "=" + solution); >else if(operand.equals("-")) < int solution = firstnum - secondnum; System.out.println(firstnum + operand + secondnum + "=" + solution); >else if(operand.equals("/")) < int solution = firstnum / secondnum; System.out.println(firstnum + operand + secondnum + "=" + solution); >else < System.out.println("Did not recognize operation type please restart program."); return; >> else if(choice == 2) < System.out.println("Advanced equation"); System.out.println("How many numbers are in your equation? max of 7\n" + "operands are chosen by typing +,-,*,or /"); int numofnumbers = scan.nextInt(); if(numofnumbers == 2)< System.out.println("enter first num"); int firstnum = scan.nextInt(); System.out.println("enter second num"); int secondnum = scan.nextInt(); System.out.println("enter operand"); String operand = scan.next(); if(operand.equals("+"))< int solution = firstnum + secondnum; System.out.println(firstnum + operand + secondnum + "=" + solution); >else if (operand.equals("*")) < int solution = firstnum * secondnum; System.out.println(firstnum + operand + secondnum + "=" + solution); >else if(operand.equals("-")) < int solution = firstnum - secondnum; System.out.println(firstnum + operand + secondnum + "=" + solution); >else if(operand.equals("/")) < int solution = firstnum / secondnum; System.out.println(firstnum + operand + secondnum + "=" + solution); >else < System.out.println("Did not recognize operation type please restart program."); return; >> else if(numofnumbers == 3) < System.out.println("enter first num"); int firstnum = scan.nextInt(); System.out.println("enter second num"); int secondnum = scan.nextInt(); System.out.println("enter thir num"); int thirdnum = scan.nextInt(); >else if(numofnumbers == 4) < System.out.println("enter first num"); int firstnum = scan.nextInt(); System.out.println("enter second num"); int secondnum = scan.nextInt(); System.out.println("enter third num"); int thirdnum = scan.nextInt(); System.out.println("enter fourth num"); int fourthnum = scan.nextInt(); >else if(numofnumbers == 5) < System.out.println("enter first num"); int firstnum = scan.nextInt(); System.out.println("enter second num"); int secondnum = scan.nextInt(); System.out.println("enter third num"); int thirdnum = scan.nextInt(); System.out.println("enter fourth num"); int fourthnum = scan.nextInt(); System.out.println("enter fifth num"); int fifthnum = scan.nextInt(); >else if(numofnumbers == 6) < System.out.println("enter first num"); int firstnum = scan.nextInt(); System.out.println("enter second num"); int secondnum = scan.nextInt(); System.out.println("enter third num"); int thirdnum = scan.nextInt(); System.out.println("enter fourth num"); int fourthnum = scan.nextInt(); System.out.println("enter fifth num"); int fifthnum = scan.nextInt(); System.out.println("enter sixth num"); int sixthnum = scan.nextInt(); >else if(numofnumbers == 7) < System.out.println("enter first num"); int firstnum = scan.nextInt(); System.out.println("enter second num"); int secondnum = scan.nextInt(); System.out.println("enter third num"); int thirdnum = scan.nextInt(); System.out.println("enter fourth num"); int fourthnum = scan.nextInt(); System.out.println("enter fifth num"); int fifthnum = scan.nextInt(); System.out.println("enter sixth num"); int sixthnum = scan.nextInt(); System.out.println("enter seventh num"); int seventhnum = scan.nextInt(); >> else

stackoverflow.com/questions/29224513/… this question of mine also needs another answer. i got one answer solved from it but it still isent working right so it would be nice if i could get some suggestions for that problem too

Instead of limiting your program to very specific input, you should think about how you can take a typical mathematical expression as a string and parse/evaluate it. Take a look here stackoverflow.com/questions/13662001/…

1 Answer 1

I love this challenge because it is so central to what computers were made for in the first place, calculating equations! What helps me to think about first is how the computer itself generally performs these kinds of operations. As I understand it the computer does one operation at a time (you got that part right!) and then stores that result and essentially re-evaluates the remaining problem as if that operation had already been done.

In order to do this kind of thing in java I think it is best to familiarize yourself with a couple concepts such as ArrayList and String.split.

You need ArrayList to hold the problem instead of the more traditional array because the length of the problem is going to change throughout the program as we can see above with the 4+3+2 example. So if you were to try to cycle through an array with a for loop but the array needs to keep getting shorter, this can all become very complicated.

ArrayList is an awesome object that provides us with an dynamic «form» of array that has all kinds of helpful methods.

You can declare an ArrayList like this.

ArrayList *Name* = new ArrayList(); 

And then you can use a bunch of different methods such as .add to add an item to the end of the list (increasing the length by 1), .remove to remove an item (and its containing index decreasing the length by 1), and .get(idx) which replaces Array[idx].

Now you are going to want to store your operators in the same object as your operands because you want to maintain their order. In order to do this your best bet is to store the whole entry as a String, like a sentence, and then later you can split the whole thing up. This is where String.split comes in.

You can check out this awesome entry on its use:

You can return an array that contains each number next to its operator in sequence.

Now this is very important!!

You cannot put the array returned from a split directly into an arraylist! You must store it in a traditional array first, and then you can «feed» it into an ArrayList using a for loop and ArrayList.add().

Now I’m not going to solve this for your, as I’m sure you’ll want to figure it out yourself. But feel free to hit me up!

Oh and last couple things. You are going to need .parseToDouble to convert the strings in the ArrayList back into doubles, and .toString to convert them back into strings and place them back into ArrayList.

Oh and you should learn to write and call methods, will make your life a lot easier in terms of organization.

For example in main instead of:

double result; double a; double b; result = a+b 

As long as your write the method beneath main:

public double add(double x, double y)

May seem like more typing at first but when you get used to writing methods like that you will find your overall code getting shorter and shorter

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A calculator created in 2020 as a project for my Java introductory course in the British University in Dubai

Mayonaka88/java-advanced-calculator

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README.md

A calculator created in 2020 as my project for the Java introductory course in the British University in Dubai.

Java was used in this project.

The calculator is entirely operated on the terminal.

The program is comprised of one file.

The calculator has 5 modes which are the Basic Calculator, the Statistical Calculator, the Matrix Calculator, the Geometeric Calculator, and the Mini Games.

In total, there are 30 operations that can be preformed.

An issue with this project is that it does not contain any comments however the code is readable enought to be utilized.

I suggest running the code and exploaring its capabilities because even though it is such a small project it still has many impressive capabilities like backtracking and the ability to process matrices all in the terminal.

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A calculator created in 2020 as a project for my Java introductory course in the British University in Dubai

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aepikalov/JavaPatterns_2_1_Structural

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README.md

В этом задании попрактикуемся с шаблоном Adapter (Адаптер). Ниже вам дан готовый класс калькулятора:

public class Calculator < public Formula newFormula() < return new Formula(); > public static enum Operation < SUM, SUB, MULT, DIV, POW; > public static class Formula < protected Double a, b, result; protected Formula() <> public Formula addOperand(double operand) < if (a == null) < a = operand; > else if (b == null) < b = operand; > else < throw new IllegalStateException("Formula is full of operands"); > return this; > public Formula calculate(Operation op) < if (a == null || b == null) throw new IllegalStateException("Not enough operands!"); switch (op) < case SUM: result = a + b; break; case SUB: result = a - b; break; case MULT: result = a * b; break; case DIV: result = a / b; break; case POW: result = Math.pow(a, b); break; > return this; > public double result() < if (result == null) throw new IllegalStateException("Formula is not computed!"); return result; > > >

Пример использования этого класса:

Calculator calc = new Calculator(); System.out.println( calc.newFormula() .addOperand(5) .addOperand(15) .calculate(Calculator.Operation.MULT) .result() );

Пользователю же нужен другой интерфейс для работы с калькулятором:

public interface Ints < int sum(int arg0, int arg1); int mult(int arg0, int arg1); int pow(int a, int b); >

который он использует в main , например, вот так:

public static void main(String[] args) < Ints intsCalc = new IntsCalculator(); System.out.println(intsCalc.sum(2, 2)); System.out.println(intsCalc.sum(10, 22)); System.out.println(intsCalc.pow(2, 10)); >

Вам надо написать класс IntsCalculator , который будет имплементировать интерфейс Ints , «под капотом» делая вычисления через класс Calculator .

1. Создайте класс Calculator , скопируйте его готовый код выше.
2. Создайте интерфейс Ints , скопируйте его готовый код выше.
3. Создайте класс IntsCalculator , укажите что он имплементирует интерфейс Ints , реализуйте его методы через обращение к объекту класса Calculator :

public class IntsCalculator implements Ints < protected final Calculator target; public IntsCalculator() < this.target = new Calculator(); > @Override public int sum(int arg0, int arg1) < //считаем через target > @Override public int mult(int arg0, int arg1) < //считаем через target > @Override public int pow(int a, int b) < //считаем через target > >

1. Создайте класс Main , продемонстрируйте использование и возможности вашего класса (например, как выше в условии), обращайтесь к нему как к объекту интерфейса Ints .

public class Main < public static void main(String[] args) < Ints calc = new IntsCalculator(); //демонстрация > >

1. Протестируйте работу программы. Не забывайте про правила форматирования кода (для автоформата можете выделить код в идее и нажать Ctrl+Alt+L).

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